SwiftでURLのQueryをDictionaryにパースする

前提

swift2.1

functionを定義する方法

func generateDictionalyFromUrlComponents(components: NSURLComponents) -> [String : String] {
    var fragments: [String : String] = [:]
    guard let items = components.queryItems else {
        return fragments
    }
    
    for item in items {
        fragments[item.name] = item.value
    }
    
    return fragments
}

let comp: NSURLComponents? = NSURLComponents(string: "http://example.com/?id=12345&username=tarou")
let fragments = generateDictionalyFromUrlComponents(comp!)
print(fragments["id"]) // => Optional("12345")

NSURLをextensionする方法

extension NSURL {
    var fragments: [String : String] {
        var results: [String : String] = [:]
        guard let urlComponents = NSURLComponents(string: self.absoluteString), let items = urlComponents.queryItems else {
            return results
        }
        
        for item in items {
            results[item.name] = item.value
        }
    
        return results
    }
}

let url = NSURL(string: "http://example.com/?id=12345&username=tarou")
print(url!.fragments["id"]) // => Optional("12345")